0  B17R0.43  C=C(C)CCCCCCCCCCCCCCC AM0463 [1,0,0,0,0,0|2,0,1]=4
1  B17R0.43  CCCCCCCCCCCCCCCC(C)=O AC0422 [1,0,0,0,0,0|1,0,1]=3
2  B16R0.274  CCCCCCCCCCCCCCC(C)=O AC0463 [2,0,0,0,0,0|1,0,0]=3
3  B16R0.303  C=CCCCCCCCCCCCCCCC AH0463 [2,0,0,0,0,0|1,0,1]=4