0  B11R1.464  OCC1=C(Br)C=C(F)C=C1Br AC050318 [2,0,0,0,0,0|1,1,0]=4
1  B13R2.155  BrC1=CC=C2OCC(=O)NC2=C1 AC511616 [1,0,0,1,0,0|2,0,0]=4