0  B15R1.1183  CCCNCC1=CC(C(F)(F)F)=CC=C1 EB16587 [1,0,1,0,0,0|2,0,0]=4
1  B15R1.1183  CCCNCC1=CC(C(F)(F)F)=CC=C1 EB16588 [1,0,1,0,0,0|2,0,0]=4