0  B15R2.308  FC1=CC=C(C2=C(Br)C=CC=C2)C=C1 78415 [1,0,0,0,0,0|3,0,0]=4
1  B14R2.68  C[N+]1=CC=C(C2=CC=CC=C2)C=C1 D95477 [2,0,0,0,0,0|2,0,0]=4
2  B14R2.296  NC1=C(C2=C(F)C=CC=C2)NN=C1 D85538 [1,0,0,0,1,0|2,0,0]=4